According to Hooke's law, the energy stored in spring is 1/2 kx^2. k is a constant unique to every type of spring and x is the distance compressed/stretched(for locks, compression only) from resting state.
The energy needed to push the pins up increase exponentially with the amount of displacement.
Does this make bumping a lock with a lot of shallow cuts more difficult?
Say a Schlage lock pinned to 0 0 0 0 0 0 (which is something you can open with a blank), but if you were to bump it, the bump key must provide enough acceleration to give the pins enough momentum to reach the "ceiling".
If there's a shallow cut mixed on like 0 0 5 0 7 0, the force needed to set the 0 pins might actually over shoot the shallower ones.
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Are shallower bittings harder to bump?
1 reply to this topic
Posted 05 April 2011 - 02:52 AM
Yeah, sometimes shallow cuts make it more difficult to bump. If the valleys are wider and deeper then its easy to interact with the pins easily. So try that, but it also depends on hand to hand, so you will get the desired answer yourself after some practice.